-t^2+2=t+12

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Solution for -t^2+2=t+12 equation: 



-t^2+2=t+12

We move all terms to the left:

-t^2+2-(t+12)=0

We add all the numbers together, and all the variables

-1t^2-(t+12)+2=0

We get rid of parentheses

-1t^2-t-12+2=0

We add all the numbers together, and all the variables

-1t^2-1t-10=0

a = -1; b = -1; c = -10;
Δ = b2-4ac
Δ = -12-4·(-1)·(-10)
Δ = -39
Delta is less than zero, so there is no solution for the equation

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